Empty arrayList and empty string throws StringIndexOutOfBounds exception

Question

I am getting StringIndexOutOfBounds exception in this part of the code.
The field that captures myList is optional in the UI.This error occurs only when myList/myURL string is empty. How do I handle it?

Can someone correct me what am I doing wrong here?

    if (myList != null) {

            for (int r = 0; r < myList.size(); r++) {
                myURL = myURL + myList.toString() + ",";
            }

            myURL = myURL.substring(0, myrssURL.length() - 1);
            myURL = myURL.replace("[", "").replace("]", ""); 
        }
   else
    {
        rssList.clear();
        rssURL=null;
        System.out.println("inside else >>>>");
    }

nook · Accepted Answer · 2013-07-19 16:41:04Z

8

If your length is 0, myURL = myURL.substring(0, myrssURL.length() - 1); will evaluate to myURL = myURL.substring(0,-1); Which is where you are getting your out of bounds error.

To fix, you should check if the arrayList.isEmpty() or if the length is 0.

answered Jul 19, 2013 at 16:41

nook

2,3965 gold badges34 silver badges54 bronze badges

Sign up to request clarification or add additional context in comments.

Comments

Mena · Accepted Answer · 2013-07-19 16:40:53Z

4

Check for empties?

if (myList != null && !myList.isEmpty()) {

// same code as before
}

answered Jul 19, 2013 at 16:40

Mena

48.6k11 gold badges90 silver badges110 bronze badges

Collectives™ on Stack Overflow

Empty arrayList and empty string throws StringIndexOutOfBounds exception

2 Answers 2

Comments

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

2 Answers 2

Comments

Comments

Your Answer

Sign up or log in

Post as a guest

Related