How to create .EXE file in python using cx_freeze

Question

I have one application developed in python 3.2, which has inbuilt modules(ex: Tkinter, matplotlib, openpyxl), user defined modules & classes(ex: draw_graph, generate_report), icon files, log file, .csv, .docx etc. I am running this application from script(ex: testapplication.py)

I have setup file as

import sys
from cx_Freeze import setup, Executable
exe = Executable(
    script=r"C:\Python32\testapplication.py",
    base="Win32GUI",
    )

setup(
    name = "TESTApp",
    version = "0.1",
    description = "An example",
    executables = [exe]
    )

Now I want to create a exe file of this application. can anyone please suggest me a way to do this?

The-IT · Accepted Answer · 2013-07-23 08:49:56Z

3

So this is what you need to do. For starters, change script=r"C:\Python32\testapplication.py" to script=r"testapplication.py"

Then, put ALL the files to need to convert into C/python32 including the setup file. Then what you wan to do is get your command line up, and type the following commands: (assuming that you're cx_freeze file is named setup.py):

cd
cd python32
python setup.py build

And then you should have a build folder in that directory containing the exe file.

answered Jul 23, 2013 at 8:49

The-IT

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