Does exists a JS or jQuery function to intersect 2 arrays, for example:
var array1 = [1,2,3,4,5];
var array2 = [2,4,8,9,0];
var result = someFun(array1, array2);
//result = [2,4];
sure I can make it manually, but maybe exists a shorter way.
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4The answer to your actual question (whether such a function exists) is: no.Felix Kling– Felix Kling2013-07-23 08:44:54 +00:00Commented Jul 23, 2013 at 8:44
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@FelixKling Ok, thanks, that what I soughtIgorCh– IgorCh2013-07-23 08:48:20 +00:00Commented Jul 23, 2013 at 8:48
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2 Answers
Since you have jQuery tag:
$(array1).filter(array2);
Or:
$.map(array1, function(el){
return $.inArray(el, array2) < 0 ? null : el;
})
Or (not for IE8 or less):
array1.filter(function(el) {
return array2.indexOf(el) != -1
});
Example:
> array1 = [1,2,3,4,5];
[1, 2, 3, 4, 5]
> array2 = [2,4,8,9,0];
[2, 4, 8, 9, 0]
> array1.filter(function(el) {
return array2.indexOf(el) != -1
});
[2, 4]
6 Comments
VisioN
Where is the jQuery here?
mishik
Hm... I'm not sure that
filter will work in IE8 or less without jQuery, but I might be wrong.VisioN
Then you should provide jQuery solution, since
array.filter() is a prototype method. jQuery method is called $.grep().
Andrew
Not sure what all the fuss is about. I can use "filter", "not", and so on with a jQuery array. no issues. This is the intersection, true, but also answers a more general question
i--
Never realized
$(array1).filter(array2) could do pure array manipulations. That helped! |
This Should work
var alpha = [1, 2, 3, 4, 5, 6],
beta = [4, 5, 6, 7, 8, 9];
$.arrayIntersect = function(a, b)
{
return $.grep(a, function(i)
{
return $.inArray(i, b) > -1;
});
};
console.log( $.arrayIntersect(alpha, beta) );
