php dropdown select error

Question

I have the following code and it insert the necessary data to the database perfectly. but the problem is that when i want to implement select="select".. so that if the customer return he will see what he choose from the dropdown menu...how can i do that, any idea...

<pre>
<?php
//array generated from mysql to feed first dropdown menu.
$newOptions = array();
    foreach ($input as $option) {
        $wclID = $option['desc'];
        $nameF = $option['fame'];
        $nameL = $option['lname'];
        $id = $option['ID'];
        $newOptions[$wclID][$id] = $nameL." ".$nameF;
    }

//second array for second dropdown menu
$array = array('ent','res');    
?>


   <div class="control-group">
        <div class="controls">
            <form  id="checkEnt" name="che" method="post" action="com.php?ID=<?=$ID?>">
                <input type="hidden" value="che" name="ent">
                <table class="table table-striped span10">
                    <tbody>
                        <? foreach ($newOptions as $wclID => $list) {  ?>
                            <tr><td width="5%">
                                    <h5><?=$wclID?> AA</h5>
                                </td>
                                <td width="10%">
                                    <label class="control-label" for="inputWei"><?=_('Boy')?></label>  
                                    <select class="input-xlarge" id="input" name="drop[0][]">   
                                        <option value=""><?=_('[select]')?></option>
                                        <?php 
                                            foreach ($list as $key => $value) {
                                            ?><option value="<?=$key?>"><?=$value?></option>

                                            <?php    } ?>
                                    </select>
                                </td>
                                <td width="10%">
                                    <label class="control-label" for="inputWei"><?=_('Res')?></label>
                                    <select class="input-xlarge" id="drop" name="drop[1][]">
                                        <option value=""><?=_('[select]')?></option>
                                        <?php
                                         foreach ($array as $key => $value) {
                                            ?><option value="<?=$value?>"><?=$value?></option>

                                            <?php } ?>
                                    </select>
                                </td>
                            </tr>

                              <?
                            }
                        ?> 

                            <tr><td colspan="3">
                                    <div class="modal-footer">
                                        <button type=reset class="btn btn-danger"><?=_('Reset')?></button>
                                        <button class="btn btn-primary" ID="btnSave"><?=_('Save')?></button>
                                    </div>
                                </td>
                            </tr> 


                    </tbody>
                </table> 
            </form>   
        </div>
    </div>
</pre>

What is going on with your form action? Your PHP declaration is part of the action statement. — Sablefoste
– Sablefoste, Commented Jul 23, 2013 at 15:35
ohhh, sorry for saying error...question..how could i implement the select="selected" attribute...on this code? — Mr Internet
– Mr Internet, Commented Jul 23, 2013 at 15:36
what the action does is send the data to mysql table and properly saved. i use pdo function to achieve this... — Mr Internet
– Mr Internet, Commented Jul 23, 2013 at 15:37
possible duplicate of stackoverflow.com/questions/3747212/… — Sablefoste
– Sablefoste, Commented Jul 23, 2013 at 15:38

zazvorniki · Accepted Answer · 2013-07-23 17:58:20Z

2

I recently did something similar to this. This is for data that is coming back from the database correct? If so then I would implement something similar to this.

On the option tags I would try an if statement to see what is in the database and then if it is call the selected=selected

<option value="Something" <? if(in_array('Something',$nameofArray)) echo 'selected="selected"';?>>Something</option>

or in your case you might want to try

<?foreach ($list as $key => $value) {?>
    <option value="$value" <? if($value) echo 'selected="selected"';?>>$value</option>

 <?}?>

edited Jul 23, 2013 at 17:58

answered Jul 23, 2013 at 15:40

zazvorniki

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7 Comments

Mr Internet Over a year ago

which array we are taking about, in_array('Something',$nameofArray) could u please elaborate

zazvorniki Over a year ago

That was just an example. this in_array is where your information coming from the database should be. So in your case it would just be $value so if your value is there then it will be selected. Make sense?

Mr Internet Over a year ago

$html_form .= '<option value="'.$value.'"'. if($value) echo 'selected="selected">'.$value.'</option>'; why i get error

Mr Internet Over a year ago

hi zazvorniki, could you please see the above code and suggest please how could i insert selected="selected" attribute..Please?

Mr Internet Over a year ago

i see this code....of yours..<?foreach ($list as $key => $value) {?> <option value="$value" <? if($value) echo 'selected="selected"';?>>$value</option> <?}?>

|

zjm555 · Accepted Answer · 2013-07-23 15:34:59Z

-1

Use the "selected" attribute of the option tag:

http://www.w3schools.com/tags/att_option_selected.asp

answered Jul 23, 2013 at 15:34

zjm555

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1 Comment

Mr Internet Over a year ago

but how? i just put like this <option value="<?=$key?>" select="selected"><?=$value?></option>

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