Hey I would like to convert a string to a number
x="0.80"
#I would like to convert x to 0.80 to compare like such:
if[ $x -gt 0.70 ]; then
echo $x >> you_made_it.txt
fi
Right now I get the error integer expression expected because I am trying to compare a string.
thanks
you can use bc
$ echo "0.8 > 0.7" | bc
1
$ echo "0.8 < 0.7" | bc
0
$ echo ".08 > 0.7" | bc
0
therefore you can check for 0 or 1 in your script.
If your values are guaranteed to be in the same form and range, you can do string comparisons:
if [[ $x > 0.70 ]]
then
echo "It's true"
fi
This will fail if x is ".8" (no leading zero), for example.
However, while Bash doesn't understand decimals, its builtin printf can format them. So you could use that to normalize your values.
$ x=.8
$ x=$(printf %.2 $x)
$ echo $x
0.80
For some reason, this solution appeals to me:
if ! echo "$x $y -p" | dc | grep > /dev/null ^-; then echo "$x > $y" else echo "$x < $y" fi
You'll need to be sure that $x and $y are valid (eg contain only numbers and zero or one '.') and, depending on how old your dc is, you may need to specify something like '10k' to get it to recognize non-integer values.
Here is my simple solution:
BaseLine=70.0 if [ $string \> $BaseLine ] then echo $string else echo "TOO SMALL" fi
use awk
x="0.80"
y="0.70"
result=$(awk -vx=$x -vy=$y 'BEGIN{ print x>=y?1:0}')
if [ "$result" -eq 1 ];then
echo "x more than y"
fi
The bash language is best characterized as a full-featured macro processor, as such there is no difference between numbers and strings. The problem is that test(1) works on integers.
