How to replace command name when invoking as bash script?

Question

I have a symlink that points to some program: git-receive-pack -> git. I want to replace symlink with bash script and then call git as if it was called from symlink before replacement. I tried to call it as git $* but it sees first argument as git and not as git-receive-pack. How to invoke it correctly?

Endrju · Accepted Answer · 2013-07-29 21:44:35Z

3

I would leave the git-receive-pack symlink alone, instead create a bash function (in ~/.bashrc). Something like this should do the trick:

function git-receive-pack() {
   ... (do your stuff)
   command git-receive-pack $*
}

answered Jul 29, 2013 at 21:44

Endrju

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3 Comments

Carl Norum Over a year ago

You could use command git-receive-pack to keep your PATH working instead of hardcoding /usr/bin, too.

Poma Over a year ago

Will that work for non-interactive shells? Like git push [email protected]:repo.git

Endrju Over a year ago

Check for BASH_ENV environment variable, which is used for non-interactive shells. It should be set already. If it's unset, export it from .bash_profile as export BASH_ENV=~/.bashrc. The function will work.

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