re-order associative array based on reference associative array

Question

I have two associative arrays

$reference = array(
  'type_drink' => 'value', 
  'type_plate' => 'value', 
  'type_fork' => 'value', 
  'non_type' => 'value'
);
$target = array(
  'type_plate' => 'value other', 
  'type_drink' => 'value other'
);

What's a nice way to re-order target to match $reference order of keys and ignoring keys that are not present in $target so that the final

$target = array(
  'type_drink' => 'value other',
  'type_plate' => 'value other' 
);

I was gonna say array_intersect_key($target, $reference), but then I noticed you wanted the array sorted. — gen_Eric
– gen_Eric, Commented Aug 1, 2013 at 20:36

Izodn · Accepted Answer · 2013-08-01 20:45:48Z

2

Not sure if this is what you need, but here's what I interpret what you're asking for.

foreach($reference as $key => $val)
{
    if(isset($target[$key]))
        $tmp[$key] = $target[$key];
}
$target = $tmp;

edited Aug 1, 2013 at 20:45

answered Aug 1, 2013 at 20:40

Izodn

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3 Comments

ironcito Over a year ago

I'd say $tmp[$key] = $target[$key], if I'm reading his question correctly.

gen_Eric Over a year ago

That seems to me what he is looking for. Though, he may actually want $tmp[$key] = $target[$key];

Izodn Over a year ago

@RocketHazmat Now that you mention it, that looks right. THe values per key are different. So I'll edit.

Kai · Accepted Answer · 2013-08-01 20:39:46Z

0

http://php.net/manual/en/function.array-intersect-key.php and http://php.net/manual/en/function.ksort.php

ksort(array_intersect_key($target, $reference));

answered Aug 1, 2013 at 20:39

Kai

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1 Comment

gen_Eric Over a year ago

That will sort the keys, but not in the order he wants. Also, you can't the result of array_intersect_key to ksort.

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