How can I include 2 php files variables?

Question

i describe my question with example:

-index.php file content:

<?php
require_once(funcfile1.php);
include(funcfile2.php);
?>
<div><?php echo $var1; ?></div>

-funcfile1.php content:

<?php
$var1 = 'html codes'.$var2.'htmlcodes'.**[MY QUESTION]**.'other html or php cods'
?>

you see in index file echo $var1 that is in funfile1.php

but now i want add a variable for echo in [MY QUESTION] that this variable need funcfile2.php include

and funcfile2 just include in index.php

what can i do?

what you got when try your example

Gowri
– Gowri

2013-08-02 13:20:38 +00:00
Commented Aug 2, 2013 at 13:20 — Gowri
– Gowri, Commented Aug 2, 2013 at 13:20
Can you show us your real code instead?

Xyz
– Xyz

2013-08-02 13:21:08 +00:00
Commented Aug 2, 2013 at 13:21 — Xyz
– Xyz, Commented Aug 2, 2013 at 13:21

Code Lღver · Accepted Answer · 2013-08-02 13:44:19Z

2

include the funfile2.php into funfile1.php. and when you will include the funfile1.php in index.php then funfile2.php file will also be include in index.php file.

-funcfile1.php content:

<?php
include(funcfile2.php);
$var1 = 'html codes'.$var2.'htmlcodes'.**[MY QUESTION]**.'other html or php cods'
?>

And index.php content will be:

<?php
require_once(funcfile1.php); 
// remove include funcfile1.php from here as it was includeed in funcfile1.php
?>

edited Aug 2, 2013 at 13:44

answered Aug 2, 2013 at 13:24

Code Lღver

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