let's say i have 2 classes
class B
{
B() { /* BLA BLA */ };
B(int a) { /* BLA BLA */ };
B(int a,int b) { /* BLA BLA */ };
}
class A {
public :
A(B par);
}
i was wondering how can i call A's constructor with par having a deafult argument, as each of B constructors. (of course i would like see 3 examples, i don't expect all of them to exist together)
thanks
You can do something like:
A(B par = B())
A(B par = B(1))
A(B par = B(1,2))
Full code as per comment:
class B
{
public:
B() { };
B(int a) {};
B(int a,int b) {};
};
class A {
public :
A(B par = B()/* or B(1) or B(1,2) */);
};
par as object of B and pass the same to A, then it did not work for me, though I am not the down voter.A(B());//create a B object and pass it to A
A(B(1));
A(B(1,2));
or define 3 different constructor for A(but that does not sound good to me).
