0

I'm struggling whit this... Basically, I have a script that will run every day (cron job). This script has to retrieve data from a table and it will post the data in another table (same database).

Here is my example script:

<?php

$c = mysql_connect("localhost", "user", "password");
$db = mysql_select_db("mydb", $c);


$query_sel = "SELECT id, rating, rating_count FROM mytableone";
$result_sel = mysql_query($query_sel) or die(mysql_error());
$ids = array();

while($id = mysql_fetch_array($result_sel))

    $ids[] = $row;

foreach($ids as $id){ 

$lid = $row['id'];
$etvalue = $row['user_rating'];
$etcount = $row['rating_count'];

mysql_query("INSERT INTO mytabletwo VALUES ('$lid','$etvalue','$etcount',CURRENT_DATE())");

}
?>

My main idea is to insert data (as mysql query in foreach statement) "for each id from mytableone".

Where is my fault?

Thanks

2

2 Answers 2

1

You can do this with one SQL query

INSERT INTO mytabletwo SELECT id,rating,rating_count,CURRENT_DATE() FROM mytableone

As to the fault you are using $row instead of $id[...]

Sign up to request clarification or add additional context in comments.

1 Comment

I have it, thank you. You're right. This is the simplest way. Many thanks!
1

The easiest way to do this is:

INSERT INTO mytabletwo(idColumnName, ratingColumnName, rating_countColumnName, dateColumnName) SELECT id, rating, rating_count, CURRENT_DATE() FROM mytableone;

(That is one statement.)

Comments

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Start asking to get answers

Find the answer to your question by asking.

Ask question

Explore related questions

See similar questions with these tags.