In array find match and replace it by jQuery

Question

Here have a array set:

totalarray =[
             [1,2,3,4],
             [8,9,10],     
             [15,16,17],
             [8,14,20]
            ]

And I need to make it combine if which set have a same number.

like that:

totalarray =[
             [1,2,3,4],
             [8,9,10,14,20],
             [15,16,17]
            ]

Other example:

totalarray =[
[1,2,3,4],
[6,10,19],
[6,16,4],
[4,14,20]
]

to

totalarray =[
[1,2,3,4,6,10,14,16,19,20]
]

So, I need to make it if any number match on other array and make it to together. e.g:

Array = [[1,2,3,4],[8,9,10],[8,11,12]];

Array[1][0] and Array[2][0] is match, so Array will become Array = [1,2,3,4],[8,9,10,11,12].

Any suggestion?

I'm not sure I understand your question. You mean which has a repeated number ? Can you explain more please? — Sergio
– Sergio, Commented Aug 10, 2013 at 7:04
Sorry, I need to make it if any number match on other array and make it to together. e.g: Array = [1,2,3,4],[8,9,10],[8,11,12]; Array[1][0] and Array[2][0] is match, so Array will become Array = [1,2,3,4],[8,9,10,11,12]. Thanks for fast reply. — ronicken
– ronicken, Commented Aug 10, 2013 at 7:11
so you want to join only the arrays that have a value in common? are you sure there's no better way to approach this? merge all arrays and remove duplicates for example? — omma2289
– omma2289, Commented Aug 10, 2013 at 7:17
Your second example seems wrong : there's no common value between the arrays 0+3 and the arrays 1+2. — Denys Séguret
– Denys Séguret, Commented Aug 10, 2013 at 7:26

Denys Séguret · Accepted Answer · 2013-08-10 10:00:02Z

1

You have to write the boring looping code. But you might make it a little more manageable with

[].push.apply(arr1, arr2); : it pushes all elements of arr2 to arr1 without building a new array
indexOf : it looks for an element in an array. If you want to support IE8, as you tagged the question jquery, then you may use $.inArray

Here's the code :

var totalarray =[
  [1,2,3,4],
  [8,9,10],     
  [15,16,17],
  [8,14,20]
];
var result = [totalarray[0]];
function prec(tai) {
  for (var j=0; j<result.length; j++) {
    for (var k=0; k<tai.length; k++) {
      if (result[j].indexOf(tai[k])!=-1) {
        return result[j];
      }
    }
  }
  return null;
}
for (var i=1; i<totalarray.length; i++) {
  var arr = prec(totalarray[i]);
  if (arr) [].push.apply(arr, totalarray[i]);
  else result.push(totalarray[i]);
}

result is the array you want.

Demonstration

edited Aug 10, 2013 at 10:00

answered Aug 10, 2013 at 7:22

Denys Séguret

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Comments

L10 · Accepted Answer · 2013-08-10 07:15:29Z

0

If i understood correctly you are trying to get union

You use the library underscore you can write like this

_.union([1, 2, 3], [101, 2, 1, 10], [2, 1]);
=> [1, 2, 3, 101, 10]

Link: Underscore.js

answered Aug 10, 2013 at 7:15

L10

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1 Comment

Denys Séguret Over a year ago

Well, that really doesn't look like what OP asks for.

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