python 2.3 regex problem

Question

how do i set the regular expressions flags like multiline and ignorecase in python 2.3?

in python 2.6 its like this

re.findall(pattern,string, re.multiline | re.ignorecase)

but this doesn't seem to wok for python 2.3, any ideas?

pointers appreciated

edit: sorry, it was python 2.3 not 2.4

re.multiline doesn't work on 2.6 or any other version-- there's no such attribute. The names of those flags (like all module-level constants) are in UPPERCASE in all Python versions. When asking a question, show the code that you actually ran, and don't type it from memory, use copy/paste. — John Machin
– John Machin, Commented Nov 30, 2009 at 11:31

Aaron Digulla · Accepted Answer · 2009-11-30 09:03:08Z

1

Compile the regexp in advance with re.compile(pattern[, flags]). Then you can pass the options as the second parameter.

answered Nov 30, 2009 at 9:03

Aaron Digulla

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Kimvais · Accepted Answer · 2009-11-30 09:03:48Z

1

the flags are uppercase in 2.4, e.g.:

re.findall(pattern,string, re.MULTILINE | re.IGNORECASE)

works for me;

Python 2.4.3 (#1, Sep  3 2009, 15:37:37) 
[GCC 4.1.2 20080704 (Red Hat 4.1.2-46)] on linux2
Type "help", "copyright", "credits" or "license" for more information.
>>> import re
>>> re.findall("Test","Test\ntest\nTEST",re.MULTILINE|re.IGNORECASE)
['Test', 'test', 'TEST']

answered Nov 30, 2009 at 9:03

Kimvais

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