shell scripting variables addition

Question

If I have a variable as

month=02 and when I add one to it as month=`expr $month + 1` then it becomes month=3 but I want it to be month=03 what shall I do for this?

even when I add

month=`expr $month + 01`

it doesn't work.

devnull · Accepted Answer · 2013-08-12 12:21:20Z

2

Use printf:

$ month=1
$ printf "%02d" $month
01

This approach would work when month is double-digit number.

$ month=11
$ printf "%02d" $month
11

[You can also increment a variable by saying let month++.]

answered Aug 12, 2013 at 12:21

devnull

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