test = [[None for e in range(1)] for e in range(len(foobar)/2)]
for delete in range(0,len(test)):
del test[delete][0]
This is not the most pythonic way to create an empty list
would you suggest something else?
I know that this question explains it. but this is not a duplicate of the previous one as you can see.
Does this do what you want?
test = [[] for e in range(len(foobar)/2)]
It has the same output as your code
[]*10 concatenates an empty list with itself 10 times, which results in...an empty list. [[]]*10 is a little closer, but it has the problem that @SvenMarnach describes.test = [[None for e in range(1)] for e in range(len(foobar)/2)]
can be simplified to:
test = [[] for i in xrange(len(foobar)/2)]
Also don't forget to use xrange instead of range, as it returns a generator and not a complete list
range returns a generator object starting in python 3.
An empty list:
test = []
Unless we're missing something ;-)
Or you want an list of empty lists of a given length?
n = 100
test = [ [] for i in range(0,n) ]
test = map(lambda x: [], foobar[:len(foobar)/2])
