Finding an existing key in multi-dim array

Question

So got a slight problem that I've tried my best to solve but without success. I have a Facebook app that accesses checkin information and as such goes through the API which produces the JSON output in a multi-dimensional array. I'm coding in PHP.

Problem I've got is not every checkin has the coordinate/location information (latitude / longitude) so it will come back with an error on the page.

I want to go through the array of information and find out if the key exists and/or if there is any information contained within it.

foreach ($checkins['data'] as $checkin) {
      echo ("<p>{$checkin['place']['location']['latitude']}</p>");
      echo ("<p>{$checkin['place']['location']['longitude']}</p>");
}

That is the code I use but like I say if there isn't any location information I get an error. Does anyone know how I could solve this issue or is there an easy way of looping through and finding out if the specific keys exist?

Any help would be much appreciated!

Thank you!

Jurik · Accepted Answer · 2013-08-19 11:36:24Z

1

Check if the content you're looking for exists with isset():

foreach ($checkins['data'] as $checkin) {
      if(isset($checkin['place']) 
         && isset($checkin['place']['location'])
         && isset($checkin['place']['location']['latitude'])
         && isset($checkin['place']['location']['longitude'])
      ) {
           echo ("<p>{$checkin['place']['location']['latitude']}</p>");
           echo ("<p>{$checkin['place']['location']['longitude']}</p>");
      }
}

answered Aug 19, 2013 at 11:36

Jurik

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RiggsFolly · Accepted Answer · 2013-08-19 11:35:15Z

0

Try this:

foreach ($checkins['data'] as $checkin) {
     if ( array_key_exists( 'place', $checkin ) &&
          array_key_exists( 'location', $checkin['place'] ) &&
          array_key_exists( 'latitude', $checkin['place']['location'] ) &&
          array_key_exists( 'longitude', $checkin['place']['location'] )
        ) 
     {
         echo ("<p>{$checkin['place']['location']['latitude']}</p>");
         echo ("<p>{$checkin['place']['location']['longitude']}</p>");
    }
}

answered Aug 19, 2013 at 11:35

RiggsFolly

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