Detect and extract image url from text and html tags

Question

How can i detect if there is some image html tag inside a text and extract just the url of the image ?

Eg.

Extract this url :

http://
www.someurl.com/somefileprocessor.php/12345/somedir/somesubdir/someniceimage.j
pg

from this tag (this tag can be inside another bunch of text and/or html)

<img title="Some nice title" border="0"
hspace="0" alt="some useful hint" src="http://
www.someurl.com/somefileprocessor.php/12345/somedir/somesubdir/someniceimage.j
pg" width="629" height="464" />

Thank's in advance Ângelo

Seems like the answer is here: stackoverflow.com/questions/2143202/…. — bredikhin
– bredikhin, Commented Aug 26, 2013 at 18:47

animuson · Accepted Answer · 2014-07-21 21:45:38Z

2

A quick attempt at an <img/> tag specific regex:

preg_match_all('/<img[^>]*?\s+src\s*=\s*"([^"]+)"[^>]*?>/i', $str, $matches);

Example

edited Jul 21, 2014 at 21:45

animuson♦

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answered Aug 26, 2013 at 19:11

Emissary

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1 Comment

Frizi Over a year ago

There should be at least one whitespace between img and src attribute. You should add a \s+. This fails: <img data-active-src="active.png" src="standard.png">

Moein Hosseini · Accepted Answer · 2013-08-26 19:19:46Z

1

You can use CRUL to get content and then extract all img tags from content. to get data by curl:

function get_data($url) {
    $ch = curl_init();
    $timeout = 5;
    curl_setopt($ch, CURLOPT_URL, $url);
    curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
    curl_setopt($ch, CURLOPT_CONNECTTIMEOUT, $timeout);
    $data = curl_exec($ch);
    curl_close($ch);
    return $data;
}

then use regular expression to extract data.

^https?://(?:[a-z\-]+\.)+[a-z]{2,6}(?:/[^/#?]+)+\.(?:jpg|gif|png)$

this helps you to extract all image urls(in img tag or not).

If you need crawler ,you can use PHPCrawl

answered Aug 26, 2013 at 19:19

Moein Hosseini

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Comments

Ângelo Rigo · Accepted Answer · 2013-08-27 20:15:56Z

0

Thank's a lot for the awnswers, as i learn some more PHP. I try this quick and dirty way, it also extracts the image url

$imageurl    = strstr($title, 'src',FALSE);
$imageurl    = strstr($imageurl,'"',FALSE);
$imageurlpos = strpos($imageurl,'"');
$imageurl    = substr($imageurl,$imageurlpos+1);
$imageurlpos = strpos($imageurl,'"');
$imageurl    = substr($imageurl,0,$imageurlpos);

answered Aug 27, 2013 at 20:15

Ângelo Rigo

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