Argument Exception when creating JObject

Question

If I have this method:

public void doSomething (Dictionary<String, Object> data)
{
    JObject jsonObject = new JObject(data);
    ...
}

I get a System.ArgumentException on the line where I create the JObject. I'm using Newton-King's Json.net wrapper.

The error I get is:

A first chance exception of type 'System.ArgumentException' occurred in Newtonsoft.Json.DLL An exception of type 'System.ArgumentException' occurred in Newtonsoft.Json.DLL but was not handled in user code

What am I doing wrong here?

Posting your whole error is helpful as well.. is it Could not determine JSON object type for type System.Collections.Generic.KeyValuePair2[System.String,System.String].`? — crthompson
– crthompson, Commented Aug 28, 2013 at 19:26
@paqogomez The error message is A first chance exception of type 'System.ArgumentException' occurred in Newtonsoft.Json.DLL An exception of type 'System.ArgumentException' occurred in Newtonsoft.Json.DLL but was not handled in user code — Nii Laryea
– Nii Laryea, Commented Aug 28, 2013 at 19:30
Have you tried using JObject.Parse and passing in your json string? I'm not sure if that would be the string, or object portion of your method, but parse returns a jobject. — crthompson
– crthompson, Commented Aug 28, 2013 at 19:30

Brian Rogers · Accepted Answer · 2015-10-21 17:37:36Z

112

The JObject(object) constructor is expecting the object to be either a JProperty, an IEnumerable containing JProperties, or another JObject. Unfortunately, the documentation does not make this clear.

To create a JObject from a dictionary or plain object, use JObject.FromObject instead:

JObject jsonObject = JObject.FromObject(data);

To create a JObject from a JSON string, use JObject.Parse, e.g.:

JObject jsonObject = JObject.Parse(@"{ ""foo"": ""bar"", ""baz"": ""quux"" }");

edited Oct 21, 2015 at 17:37

answered Aug 28, 2013 at 19:52

Brian Rogers

130k31 gold badges315 silver badges315 bronze badges

Sign up to request clarification or add additional context in comments.

2 Comments

Nii Laryea Over a year ago

how about creating a JObject from a string? How do you do that?

crthompson Over a year ago

JObject.Parse(myJsonString)

Collectives™ on Stack Overflow

Argument Exception when creating JObject

1 Answer 1

2 Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

2 Comments

Your Answer

Sign up or log in

Post as a guest

Related