Split a string with any of the words in an array

Question

Suppose I have a string like this:

Ch #RoKamb93 ajesop de Bourg #kin #kinnl 9 kunsho taffetas,bunughs rges, note florale,parfaite aseref

My array of delimiters can be :

array('#kin', '#kinnl', '#xxx' );

How can Iparse it to get the Ch #RoKamb93 ajesop de Bourg substring ? Substring just before #kin OR #kinnl

Note: Both #kin OR #kinnl may not present at the same time.

Can you please be more specific on the rules by which you want to parse the string? Also ... whathaveyoutried.com — Vlad Preda
– Vlad Preda, Commented Sep 5, 2013 at 10:38

cmbuckley · Accepted Answer · 2013-09-05 10:50:47Z

1

How about this:

$string = 'Ch #RoKamb93 ajesop de Bourg #kin #kinnl 9 kunsho taffetas,bunughs rges, note florale,parfaite aseref';

$delimiters = array('#kin', '#kinnl', '#xxx');
$pattern = '/' . implode($delimiters, '|') . '/';

$split = preg_split($pattern, $string);
var_dump($split); // $split[0] has what you need

If your delimiters contain reserved regex characters (like . or ?), you'll need to do something like this for the pattern:

$pattern = '/' . implode(array_map('preg_quote', $delimiters), '|') . '/';

edited Sep 5, 2013 at 10:50

answered Sep 5, 2013 at 10:45

cmbuckley

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