Php html selected field issue

Question

following is my part of html form. If the form is showing a error then i want to select the user selected field. But unfortunately it's not working for me. can you guys help me plz?

My html form:

<select class="td" name="class_name">
    <option value="">--Select class--</option>
    <?php
    $class = mysql_query("SELECT * FROM e_class");

    while($res =  mysql_fetch_array($class))
    {           
        $class_name_ed = $res['class_name'];
        $class_id_ed = $res['class_id'];
        ?>
        <option value="<?php echo "$class_name_ed"; ?>" <?php 
if(isset($_POST['class_name']) == "$class_name_ed") echo 'selected = "selected"';  ?>> 
<?php echo $class_name_ed; ?></option>";
        <?php
    }
    ?>
</select>

But if i look at the source file then i can see following.. It's selected all the field

<select class="td" name="class_name">
    <option value="">--Select class--</option>
    <option value="Three" selected = "selected"> Three</option>";
    <option value="Four" selected = "selected"> Four</option>";
    <option value="Five" selected = "selected"> Five</option>";
</select>

Update: If the option is look like then what can i do:

<option value="<?php echo "$class_name_ed | $class_id_ed"; ?>" <?php if 
(isset($_POST['class_name']) && ($_POST['class_name'] == $class_name_ed)) echo 
'selected = "selected"';  ?>> <?php echo $class_name_ed; ?></option>

how does your DB structure look?

Tatarin
– Tatarin

2013-09-06 16:18:35 +00:00
Commented Sep 6, 2013 at 16:18 — Tatarin
– Tatarin, Commented Sep 6, 2013 at 16:18

Marc B · Accepted Answer · 2013-09-06 16:18:27Z

2

if(isset($_POST['class_name']) == "$class_name_ed")
   ^^^^^^

you're comparing a boolean true/false value against a string. Most likely you want something more like:

if (isset($_POST['class_name']) && ($_POST['class_name'] == $class_name_ed)) {

instead.

answered Sep 6, 2013 at 16:18

Marc B

362k44 gold badges433 silver badges508 bronze badges

Sign up to request clarification or add additional context in comments.

2 Comments

Hassan Khodadadeh Over a year ago

And also change <?php echo $class_name_ed; ?></option>"; to <?php echo $class_name_ed; ?></option>

Alex Over a year ago

Ok, @Marc B I'm checking it.

albert · Accepted Answer · 2013-09-06 16:27:35Z

0

Try with this code:

if(isset($_POST['class_name']) && $_POST['class_name'] == $class_name_ed) echo 'selected';

You have an error in the conditional. isset() returns true or false. Also you do not need to wrapp the variable $class_name_ed with "". If you want to be sure that is a string you can cast it like this:

if(isset($_POST['class_name']) && $_POST['class_name'] == (string)$class_name_ed) echo 'selected';

You do not need to use selected="selected" you can mark the option as selected. Three

answered Sep 6, 2013 at 16:27

albert

4,4681 gold badge26 silver badges43 bronze badges

Collectives™ on Stack Overflow

Php html selected field issue

2 Answers 2

2 Comments

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

2 Answers 2

2 Comments

Comments

Your Answer

Sign up or log in

Post as a guest

Related