How to initialize class member array with 0

Question

I have the next class and want to initialize _operators array with 0:

    //Entity.h
class Entity
{
    static const unsigned short operatorTypeColumn = 1;
    static const unsigned short outputValueColumn = 4;
private:
    mainDataType _operators[operatorsMaxCount][operatorsTableWidth];
    }

    //Entity.cpp.          I thought this should work in C++ v11
Entity::Entity(void) : _operators[operatorsMaxCount][operatorsTableWidth]
{

}

I thought this sold work in C++ v11 but i got error... how can i initialize array with 0.. with ugly for? i don't want make it static

You forgot the trailing () on your array initializer, and you don't need the dimensions there; only in the decl. I.e. ` : _operator()`. sidenote: terrible name for a member var. — WhozCraig
– WhozCraig, Commented Sep 8, 2013 at 8:58
why is it terrible (in that array there are values of operators +, -, /) etc? — Brans
– Brans, Commented Sep 8, 2013 at 9:07
In a language that is often littered with the word operator, you can surely call it something else (op springs to my mind). — WhozCraig
– WhozCraig, Commented Sep 8, 2013 at 9:11
It makes senth.. there is probability of conflict but i care more abaut logic and objective clearness than abaut potential conflict... I don't think that somewhere there is public type "_operators"... And my _operators is private. I take a risk. — Brans
– Brans, Commented Sep 8, 2013 at 9:25

juanchopanza · Accepted Answer · 2013-09-08 09:02:14Z

6

You just need to value-initialize the array:

Entity::Entity() : _operators() {}
//                           ^^

This works in C++03 and C++11.

answered Sep 8, 2013 at 9:02

juanchopanza

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1 Comment

WhozCraig Over a year ago

+1 (obviously) And note, even now MS "warns" that this is an extension for C++0x3 and later (and then proceeds to do the right thing anyway, go figure). =P

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