Find element in jQuery with dynamic value

Question

I have following jquery script

var $checked = $inputs.filter(':checked');
var numChecked = $checked.length;

$checked.each(function () {
    var val = (this).value;

    if (val.indexOf("Ya") != -1) {
        alert('old val   ' + val);
        val = val.replace("Ya", "Y2a");
        alert('new val   ' + val);
        alert($(':input[value^="' + val + '"]').value);

        //$(val).attr({ 'disabled': true, 'aria-disabled': true })[flag ? 'addClass' : 'removeClass']('ui-state-disabled');
    }
});

the old value is : ltrYaxis0

the new value is : ltrY2axis0

I am able to replace but when I am trying to test whether its finding the new input or not, its saying undefined. I have to make this hidden or disable

can you show us the html of the element you're trying to match? — omma2289
– omma2289, Commented Sep 16, 2013 at 5:20
You want to find input with "Ya" value, replace it's value and find it? — Dart
– Dart, Commented Sep 16, 2013 at 6:58

Md. Parvez Alam · Accepted Answer · 2013-09-16 12:39:39Z

1

+50

Trye this

 val = val.replace("Ya", "Y2a");
       $(':input[value='+val + ']'.attr({ 'disabled': true, 'aria-disabled': true })

answered Sep 16, 2013 at 12:39

Md. Parvez Alam

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Arun P Johny · Accepted Answer · 2013-09-11 13:26:39Z

0

If I understood the requirement correctly, this will do

var $checked = $inputs.filter(':checked');
var numChecked = $checked.length;

$checked.filter(function () {
    return this.value.indexOf("Ya") != -1;
}).val(function (idx, val) {
    return val.replace("Ya", "Y2a");
}).attr({
    'disabled': true,
    'aria-disabled': true
})[flag ? 'addClass' : 'removeClass']('ui-state-disabled');

answered Sep 11, 2013 at 13:26

Arun P Johny

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3 Comments

Arun P Johny Over a year ago

what do you mean by jquery failed to load

M Akela Over a year ago

please just tell me how to find the element with dynamic value

Arun P Johny Over a year ago

look at the first part of the script $checked.filter(function () { return this.value.indexOf("Ya") != -1; })

pszaba · Accepted Answer · 2013-09-16 11:05:12Z

0

This line

var val = (this).value;

has 2 errors.

You missed the $
and not .value but .val()
```
var val = $(this).val();
```

and be careful :

    $(val).attr({ 'disabled': true, 'aria-disabled': true })

it shoul be

$(this).attr({ 'disabled': true, 'aria-disabled': true }) ...

answered Sep 16, 2013 at 11:05

pszaba

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