php : use str_replace( ); on some condition?

Question

my text:

bob have message123 and alice has message

i want:

bob have newmessage and alice has newmessage

My current code is:

$fullText= str_replace("message123", "newmessage", $fulltext);
$fullText= str_replace("message", "newmessage", $fulltext);

but it becomes:

bob have newnewmessage and alice has newmessage

'new' is repeated because str_replace(); search whole text and find replace again.
is it possible not to replace the text which is already replaced.

You can also pass array of strings as parameters in str_replace ex: str_replace( array( "message", "newmessage1" ), "newmessage", $fullText ); — bystwn22
– bystwn22, Commented Sep 15, 2013 at 19:33

r.bilgil · Accepted Answer · 2013-09-15 19:35:27Z

1

You could always use preg_replace.

In this case:

$fullText=preg_replace("/\bmessage[0-9]*/", "newmessage", $fullText);

which will replace message, message1, message2 etc.

answered Sep 15, 2013 at 19:35

r.bilgil

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r.bilgil Over a year ago

If you're not familiar with regex: / marks the beginning and end of the search string, \b looks for the beginning of a new word boundary [0-9]* looks for zero or more numbers at the end of the string "message"

George Brighton · Accepted Answer · 2013-09-15 19:36:56Z

0

For the simplest solution, you could just add spaces:

$fullText= str_replace(" message1 ", " newmessage ", $fulltext);
$fullText= str_replace(" message ", " newmessage ", $fulltext);

Or using multiple needles:

$fullText = str_replace(array(' message1 ', ' message '), array(' newmessage ', ' newmessage '), $fullText);

answered Sep 15, 2013 at 19:36

George Brighton

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Thomas · Accepted Answer · 2013-09-15 20:03:13Z

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Use the strtr() function -- it will not pass again over stuff that it already replaced:

$fullText = 'bob have message1 and alice has message without 1.';
$fullText = strtr( $fullText, array(
    "message1" => "newmessage",
    "message" => "newmessage" ) );

answered Sep 15, 2013 at 20:03

Thomas

1

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