I've got this piece of code, which should fetch the source code of the website.
$homepage = file_get_contents('http://homepage.com');
echo $homepage;
Instead of actually giving me the source code.. It's shows me the page that I'm trying to get the source code from.
Either use htmlentities or change the content type.
$homepage = file_get_contents('http://homepage.com');
echo htmlentities($homepage);
or
header('Content-type: text/plain');
$homepage = file_get_contents('http://homepage.com/');
echo $homepage;
htmlentities. If you set the header, then you won't be able to display anything else on your resultant page other than text, because it's basically doing the same thing as taking a page called index.html and renaming it to index.txt -- it won't be parsed as code anymore.Try this, using htmlspecialchars:
$homepage = file_get_contents('http://homepage.com');
echo htmlspecialchars($homepage);
That's because you're fetching the source code and (re)outputting it. Your page is just mirroring http://homepage.com.
To see the actual page source, add a Content-Type header before your echo statement:
header('Content-type: text/plain');
This tells the browser treat the source as plain text and not interpret it as HTML.
It's because you are printing the source, your browser will interpret that as a webpage. To see the actual code use:
echo htmlspecialchars($homepage);
