I know, that there is a way to get substring of a string variable:
MY_STR=abacaba
echo ${MY_STR:2:6}
Is there a way to get substring of a string given as literal constant? Something like:
echo ${"abacaba":2:6}
4 Answers
You can use cut:
$ echo abacaba | cut -c3-7
acaba
Saying -c3-7 would get characters 3 to 7 (note that the first character is denoted by 1).
For getting all the characters starting from the 3rd one, you could say:
$ echo abacaba | cut -c3-
acaba
You can also use tail:
$ echo abacaba | tail -c+3
acaba
Comments
If you don't mind using cut you could do:
echo "abacaba" | cut -c3-7
Comments
There isn't but you could have alternatives like using a function:
function getsub {
sub="${1:$2:$3}"
}
getsub abacaba 2 6
echo "$sub"
function printsub {
echo "${1:$2:$3}"
}
printsub abacaba 2 6
Comments
expr can deal with string literals.
expr substr STR POS LEN
- STR: the constant string.
- POS: the index of the first char of the substring (starting from 1).
- LEN: the length of the substring.
So in your example, it should be expr substr 'abacaba' 3 6
find . -exec bash -c "echo \"{}\" | cut -c3-" \;for example.