Xslt array and / or loop

Question

I have following question, basically i just would like to create a custom array, something like - Yellow | Red | Green

And after loop through this items using for-each and printing the values, i created something like this:

        <xsl:variable name="Colors">
           <m>Yellow</m>
           <m>Red</m>
           <m>Green</m>
        </xsl:variable>

And then i try to loop on it:

        <xsl:for-each select="$Colors">

            <xsl:value-of select ="current()" />                
        </xsl:for-each>

But i get this error: Exrpession must evalutate to a node-set $Colors

Any idea, what could be wrong?

Martin Honnen · Accepted Answer · 2013-09-18 12:13:18Z

4

With XSLT 1.0 your variable contains a result tree fragment (RTF) and you can't do anything with it but use xsl:copy-of or xsl:value-of. Fortunately most XSLT 1.0 processor support exsl:node-set or similar to convert a result tree fragment to a node set so you can use <xsl:for-each select="exsl:node-set($Colors)/m">...</xsl:for-each>, where you then need to declare xmlns:exsl="http://exslt.org/common" in your stylesheet.

answered Sep 18, 2013 at 12:13

Martin Honnen

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3 Comments

Martin Honnen Over a year ago

If you use <xsl:for-each select="exsl:node-set($Colors)/m"><xsl:value-of select="."/></xsl:for-each> then the three values should be output. If that does not work then there might be a default namespace declaration in scope in your stylesheet. You would need to change the variable declaration to <xsl:variable name="Colors" xmlns=""><m>Yellow</m>...</xsl:variable> to make sure the m elements are in no namespace and can be selected as m in XPath.

Alnedru Over a year ago

just another question, regarding this, for clarification: <m> is necessary to use to building an array or i can create an array differently?

Martin Honnen Over a year ago

You are not building an array as XSLT/XPath does not have any such data type. In XSLT 1.0 you are creating a result tree fragment which you then convert to a node-set. To structure your result tree fragment you indeed need to use elements (or more generally nodes). With XSLT 2.0 there is more flexibility as there you could define a sequence of strings with <xsl:variable name="colors" select="'Yellow', 'Red', 'Green'"/>.

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