Replace a part of the string after being found in the text of an array element

Question

I would like the fText string value int b=3, a, c=10; be changed into:

int _sc_b=3, _sc_a, _sc_c=10;

by using the text inside the array elements.

My code:

var fText = "int b=3, a, c=10;";

sc_var_int_temp[0] = "a";
sc_var_int_temp[1] = "b";
sc_var_int_temp[2] = "c";


for( var vi=0; vi<sc_var_int_temp.length; vi++ ){
    //how would i do the replacing?
}//for

GOAL: fText value will be int _sc_b=3, _sc_a, _sc_c=10;

UPDATE: tried fText.replace(sc_var_int_temp[vi], "_sc_"+sc_var_int_temp[vi] ); but hangs the system ^^

as much as possible, i intend to do the replacing using the loop

UPDATE

I realized that the answer i accepted will not work properly when fText is:

var fText = "int b=3,a ,c=10;";
//not really seperated by a single whitespace

I don't know what you're actually doing with this code, but this is a horrible way to store and assign values — TravisO
– TravisO, Commented Sep 18, 2013 at 19:57

pawel · Accepted Answer · 2013-09-21 07:56:57Z

4

It possibly won't catch every edge case, but works with your example input/output:

for( var vi=0; vi<sc_var_int_temp.length; vi++ ){
    fText = fText.split(' '+ sc_var_int_temp[vi] ).join( " _sc_" + sc_var_int_temp[vi] );
}

http://jsfiddle.net/6YgHj/

Or without the loop

fText = fText.split(' ').join(' _sc_');

http://jsfiddle.net/6YgHj/1/

So what you really want is to add a prefix to what seems like variable names in a string that declares the variables. You need a way to extract the variable names. I can't think of every possible way to declare variables in your source language. Is "int a=1, float b,c" valid? How about "int a=10, b=2*a;"?

edited Sep 21, 2013 at 7:56

answered Sep 18, 2013 at 20:02

pawel

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pawel Over a year ago

@extraRice it's one of the edge cases I had in mind in the first sentence ;)

ced-b · Accepted Answer · 2013-09-18 20:01:08Z

0

Try the following regexp:

var fText = "int b=3, a, c=10;";
fText = fText.replace(/(a|b|c)/g, "_sc_$1")

/(a|b|c)/g matches either a, b or c and assigns them as a separate match, because of the parens (). Then "_sc_$1" is the replacement whereby $1 pulls back the letter that was actually matched.

See the working fiddle here: http://jsfiddle.net/Kc2NF/

answered Sep 18, 2013 at 20:01

ced-b

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1 Comment

Justin Wood Over a year ago

Note, this will only change the one line, and not all subsequent references to the variable

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