I use the following pattern for decimal validation.
var pattern = /^([0-9]+)[.][0-9]{0,2}$/;
I need to enter only 10 digits. for example,
12345678.00
need to enter 8 digits before the dot. after dot,the 2 digits are optional. how to validate only enter 8 digits before dot symbol?
Try this!
^[\d]{1,8}([\.|\,]\d{1,2})?$
Regards..
Try this:
/^[0-9]{8}[.][0-9]{0,2}\b/g
Basically means "exactly 8 digits before the dot, and up to 2 digits after the dot". Also, if you want some regexp shorthand, you can use \d which escapes digits
/^\d{8}[.]\d{0,2}\b/g
Also, this was not clear in your question: do you want to match the two digits after the decimal if the user enters 3 or more characters? If yes, then remove the \b part and it will work for you
Use
/^[0-9]{8}[.]([0-9]{2})?$/
This should make sure you have 8 digits before the dot, and exactly 0 or 2 digits after the dot.
It sounds like what you really want is this:
/^[0-9]{8}(\.[0-9]{1,2})?$/
You can also write it like this:
/^\d{8}(\.\d\d?)?$/
This pattern makes the dot optional, and if it's present, requires either one or two digits after it. The \d is shorthand for [0-9] (they're not identical in all regex flavors, but they are in JavaScript).
As you've written it, your pattern requires the decimal point, even if there are no decimal digits. So 12345678 will fail, while 12354678. will pass. That's probably not what you want; in fact, I doubt you'd consider the second number valid.
