I have created a python dictionary which has keys in this form :
11, 10, 00, 01, 20, 21, 31, 30
The keys are string
I would like to maintain my dictionary in these sorted order:
00, 10, 20, 30, 01, 11, 21, 31
This is based on the second value of the key.
I tried this sorted(dict.items(), key = lambda s: s[1]) and got the keys like:
20, 30, 21, 31, 01, 11, 10, 00
Can somebody guide me?
You almost had it, but the key is the first item of the tuple:
sorted(dict.items(), key=lambda s: s[0])
s[0][1]
key=lambda (key, val): key[1] just to make it explicit
operator.itemgetter just to get out of the lambda mess? :Pdict() to get a dict again.A dictionary uses something called hashing and it can't be sorted as such. What you can do is use dict.keys().sort(key = lambda s: s[1]) and iterate or go on from there.
itemsreturns list of tuples where first item is key and second is value. So if You would like to sort them by keys You should use sorted(dict.items(), key = lambda s: s[0]) but in this case You got keys ascending sorted If You would like to sort as in your example 11, 10, 00, 01, 20, 21, 31, 30 > I would like to maintain my dictionary in these sorted order: 00, 10, 20, 30, 01, 11, 21, 31 You should reverse your key in sorted function sorted(dict.items(), key = lambda s: ''.join(reversed(s[0])))