Create XML attribute in c#

Question

I have the following code to write some data in an xml file. It works well but the attributes. I can not create attributes and its value for an element.

//.xml file===========================
<?xml version="1.0" encoding="utf-8"?>
<Errors>
   <Error Name="abc" ContactNo="123">
     <Description>Test</Description>
  </Error>
</Errors>

// c# code ===========================
XmlDocument xmlErrors = new XmlDocument();
xmlErrors.Load(Path.Combine(Application.StartupPath, "Errors.xml"));
XmlElement subRoot = xmlErrors.CreateElement("Error");
// subRoot.Attributes[0].Value = "Test 1";
// subRoot.Attributes[1].Value = "Test 2";
XmlElement Description = xmlErrors.CreateElement("Description");
Description.InnerText = currentData.ExamineeName;
subRoot.AppendChild(Description);
xmlErrors.DocumentElement.AppendChild(subRoot);
xmlErrors.Save(Path.Combine(Application.StartupPath, "Errors.xml"));

Would you please help me how to create an attribute and its value? Thanks.

mhs · Accepted Answer · 2013-09-25 05:15:22Z

9

XmlElement error = Errors.CreateElement("Error");
XmlAttribute errName= Errors.CreateAttribute("Name");
errName.value="abc"
error.Attributes.Append(errName);

answered Sep 25, 2013 at 5:15

mhs

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Comments

Alireza · Accepted Answer · 2022-04-15 01:29:10Z

6

Use SetAttributeValue on a XElement object:

subRoot.SetAttributeValue("Name","Test 1");
subRoot.SetAttributeValue("ContactNo","Test 1");

edited Apr 15, 2022 at 1:29

answered Sep 25, 2013 at 5:00

Alireza

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1 Comment

s.k.paul Over a year ago

There is no method SetAttributeValue, but SetAttribute. Anyway, thank you for giving the clue. You deserve upvote.

Anirudha · Accepted Answer · 2013-09-25 05:00:14Z

1

In LINQ2XML

XElement doc=new XElement("Errors",
      new XElement("Error",new XAttribute("Name","abc"),new XAttribute("ContactNo","123")),
      new XElement("Description","Test")
);
doc.Save(path);

answered Sep 25, 2013 at 5:00

Anirudha

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Comments

B.Habibzadeh · Accepted Answer · 2019-12-30 09:12:37Z

1

the simplest way is to use the following code:

error.SetAttribute("id", "value");

answered Dec 30, 2019 at 9:12

B.Habibzadeh

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