.bat Replace a char in a for loop

Question

I need to loop through a list of text files, and rewrite them inserting a part of their name in one of the first lines, like:

Original file name: 101f.htm

Original file content:

Line1
Line2
.
.
LineN

New file name: 101f_.htm

New file content:

<head> 
<meta http-equiv="Content-Type" content="text/html;charset=utf-8"> 
</head> 
<tr> 
Paciente Matricula: 101
</tr> 

Line1
Line2
.
.
LineN

I achieved some result with this .bat script:

set NOME=%%~ni_.xls
set MTR=%%~ni
for /R c:\teste\teste %%i IN (*.htm) DO (
ECHO.^<head^> > %NOME%
ECHO.^<meta http-equiv^="Content-Type" content^="text/html;charset=utf-8"^> >> %NOME%
ECHO.^</head^> >> %NOME%
ECHO.^<tr^> >> %NOME%
ECHO.Paciente Matricula: %MTR% >> %NOME%
ECHO.^</tr^> >> %NOME%
ECHO. >> %NOME%
type %%~nxi >> %NOME%
PAUSE
)

It gives me all I need, except by the line:

"Paciente Matricula: 101f"

I need to remove that "f" to the line display like:

"Paciente Matricula: 101"

Thanks in advance!

Endoro · Accepted Answer · 2013-09-25 17:53:47Z

3

try this code example:

@echo on &setlocal
for /R "c:\teste\teste" %%i IN (*f.htm) DO (
    (
    set "NOME=%%~ni_.xls"
    set "MTR=%%~ni"
    setlocal enabledelayedexpansion
    ECHO(^<head^> 
    ECHO(^<meta http-equiv="Content-Type" content="text/html;charset=utf-8"^>
    ECHO(^</head^>
    ECHO(^<tr^>
    ECHO(Paciente Matricula: !MTR:~0,-1!
    ECHO(^</tr^>
    ECHO(
    type "%%~nxi"
    )>"!NOME!"
    endlocal
)

Inside a codeblock (in the for loop from the first to the last parenthesis) you can't access % variables with changing values (%NOME%), there you must use delayed expansion and ! variables (!NOME!).

edited Sep 25, 2013 at 17:53

answered Sep 25, 2013 at 17:47

Endoro

37.7k8 gold badges54 silver badges64 bronze badges

Sign up to request clarification or add additional context in comments.

1 Comment

Marco Pineschi Over a year ago

Using setlocal enabledelayedexpansion and !MTR! solved the problem!

Marco Pineschi · Accepted Answer · 2013-09-25 19:15:08Z

0

Based on Endoro's answer, using the following replace syntax works:

set MTR=%%~ni
set MTR=!MTR:f=!

I used this sintax because the I can not grant the "f" character will be the last one, it can be followed by a space.

The script below works for the task.

setlocal ENABLEDELAYEDEXPANSION
set NOME=%%~ni_.xls
for /R c:\teste\teste %%i IN (*.htm) DO (
set MTR=%%~ni
set MTR=!MTR:f=!
ECHO.^<head^> > %NOME%
ECHO.^<meta http-equiv^="Content-Type" content^="text/html;charset=utf-8"^> >> %NOME%
ECHO.^</head^> >> %NOME%
ECHO.^<tr^> >> %NOME%
ECHO.Paciente Matricula: !MTR! >> %NOME%
ECHO.^</tr^> >> %NOME%
ECHO. >> %NOME%
type %%~nxi >> %NOME%
)

answered Sep 25, 2013 at 19:15

Marco Pineschi

233 bronze badges

1 Comment

jeb Over a year ago

You should use Endoro's way to use a block for the output and redirect the complete block only once to a file, as your way will append to each line a space

Collectives™ on Stack Overflow

.bat Replace a char in a for loop

2 Answers 2

1 Comment

1 Comment

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

2 Answers 2

1 Comment

1 Comment

Your Answer

Sign up or log in

Post as a guest

Related