Jquery loop through all the rows in a table without first row

Question

I need to loop through all rows for a particular table, and I have done it as below. At one point, I need to remove the matching table row. I couldn't figure out how to skip the first row and loop through all others. My code below is looping through all tr's.

$('#tbl_dynamic_call_dates > tbody  > tr').each(
    function() {
        console.log($(this).find(\'td:first\').text());
        if($.inArray($(this).find(\'td:first\').text(),array) == -1){
            $(this).remove();
        }

DrColossos · Accepted Answer · 2013-10-04 10:04:01Z

15

$('#tbl_dynamic_call_dates > tbody  > tr').not(":first").  [....]

to get everything BUT the first

$('#tbl_dynamic_call_dates > tbody  > tr:first'). [...]

or

$('#tbl_dynamic_call_dates > tbody  > tr').first(). [...]

to only get the first

answered Oct 4, 2013 at 10:04

DrColossos

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Reinstate Monica Cellio · Accepted Answer · 2013-10-04 10:04:59Z

8

Change your selector to this...

$('#tbl_dynamic_call_dates > tbody  > tr:not(:first)')

answered Oct 4, 2013 at 10:04

Reinstate Monica Cellio

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palaѕн · Accepted Answer · 2013-10-04 10:05:10Z

4

You can do this using the :gt() Selector like:

$('#tbl_dynamic_call_dates > tbody  > tr:gt(0)').each(function() {...});

answered Oct 4, 2013 at 10:05

palaѕн

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David Thomas · Accepted Answer · 2013-10-04 10:05:16Z

2

$('#tbl_dynamic_call_dates > tbody  > tr:gt(0)').each(/*...*/);

Or:

$('#tbl_dynamic_call_dates > tbody  > tr').first().siblings().each(/*...*/);

answered Oct 4, 2013 at 10:05

David Thomas

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