I had this piece of route in a project in Laravel 3:
Route::get(array('/Home', '/'.rawurlencode ('خانه')), function()
{
return View::make('home.index');
});
It was working correctly, till I decided to migrate it to Laravel 4. Now in Laravel 4 I get this error:
preg_match_all() expects parameter 2 to be string, array given
Are there any other way to set multiple patterns for Laravel 4 route?
You can achieve this using where with your route,
So if your route is,
Route::get('{home}', function()
{
return View::make('home.index');
})->where('خانه', '(home)?');
You can access the same using,
http://localhost/laravel/home
http://localhost/laravel/خانه
Here the http://localhost/laravel/ should be replaced with yours.
Using regex is the best way,
Route::get('{home}', function()
{
return View::make('home.index');
})->where('home', '(home|خانه)');
This will match only,
http://localhost/laravel/home
http://localhost/laravel/خانه
You can use regex in the route so maybe something like this.
Route::get('(Home|' . rawurlencode('خانه') . ')', function ()
{
return View::make('home.index');
});
If that doesn't work I'd probably just define two route's because the closure is so simple. Even if it is more complex, you could move it to a controller and point two routes at the same controller method.
