passing function argument to another function

Question

In the following piece of code, I want to pass delta argument into the function being called by fadeOut, without having to set a variable outside the scope of those functions. Is it possible?

$(window).bind('mousewheel', function(event, delta, deltaX, deltaY) {
    $('#view img').fadeOut('slow', function() {
        $('.view-loading').fadeIn('fast');
        showcase.rotate(delta);
    });
});

Isn't the variable delta already available to the inner function via the closure in your example? — Sean Vieira
– Sean Vieira, Commented Oct 8, 2013 at 23:58
you have it accessible in the scope so what is the point of providing argument to your callback? — lukaleli
– lukaleli, Commented Oct 8, 2013 at 23:59

net.uk.sweet · Accepted Answer · 2013-10-09 00:36:30Z

2

I can't really work out what the deal is with jQuery and mousewheel (it's late, I'm tired), but using jQuery 1.9.1, I can get a delta from the originalEvent property of the event object (which is in scope within your inner function. (fiddle).

$(window).bind('mousewheel', function(event) {
    $('#view img').fadeOut('slow', function() {
        $('.view-loading').fadeIn('fast');
        showcase.rotate(event.originalEvent.deltaY);
    });
});

edited Oct 9, 2013 at 0:36

answered Oct 8, 2013 at 23:54

net.uk.sweet

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Comments

Lloyd Banks · Accepted Answer · 2013-10-09 03:27:36Z

1

You have to manually define the delta with the jQuery "mousewheel" event

$(window).bind('mousewheel', function(event) {
    event = event.originalEvent;
    var delta = event.wheelDelta;
    $("#view img").fadeOut('slow', function() {
        $('.view-loading').fadeIn('fast');
        showcase.rotate(delta);
        showcase.fillRect(100, 10, 150, 100);
    });
});

answered Oct 9, 2013 at 3:27

Lloyd Banks

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