I have many places in my code doing "$.ajax" call can I define one place to handle all errors ?
I know there is "error: function ... " that I can place in each call , but I want to write it just one time
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4 Answers
How 'bout the ajaxError event?
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$.ajaxSetup({});
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T.J. Crowder
How very...terse. @OP: It sets default options for Ajax requests. Link: docs.jquery.com/Ajax/jQuery.ajaxSetup#options
haddar
$.ajaxSetup({ error: function(XMLHttpRequest, textStatus, errorThrown) { alert(XMLHttpRequest + ':' + textStatus + ':' + errorThrown); return false; } }); is this OK ?
T.J. Crowder
@haddar: There's sample code in the docs I linked (click the "Examples" tab). But that looks about right, yeah.
You should not use the $.ajaxSetup() event handler method (as stated by the JQuery docs):
http://api.jquery.com/jQuery.ajaxSetup/
Note: Global callback functions should be set with their respective global Ajax event handler methods—.ajaxStart(), .ajaxStop(), .ajaxComplete(), .ajaxError(), .ajaxSuccess(), .ajaxSend()—rather than within the options object for $.ajaxSetup().
Use the $.ajaxError() method instead:
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You can define your error handling function just once and then refer to it in the Ajax call rather than using function literals in each call.
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