I need to output this
1
22
333
4444
55555
666666
7777777
88888888
999999999
So far all I have is:
def main():
for i in range(10):
for n in range(i):
print(i)
return
main()
I get all the correct numbers, it's just not formatted correctly. If you guys could throw some hints my way I'd appreciate it.
Simply multiply the string version:
for i in range(10):
print(str(i) * i)
Output:
>>> for i in range(10):
... print(str(i) * i)
...
1
22
333
4444
55555
666666
7777777
88888888
999999999
If you have to use a nested loop, tell the print() function to not print a newline in the inner loop by setting the end option to an empty string; an empty print() call in the outer loop then suffices to add the necessary newline:
for i in range(10):
for n in range(i):
print(i, end='')
print()
Pretty much every answer stated above uses string to accomplish this problem. There is another way, a more easier way by applying simple math using the formula a_n= n * ((10^n - 1)/9) for n<=9. Please refer the snippet below (Using Python 3)
for i in range(1,n)
print i*(((pow(10,i)-1) // 9)
n = 4
Output
1
22
333
4444
def main():
for i in range(10):
for n in range(i):
print(i, end='')
print()
main()
def main(n):
for x in range(n):
if x>0:
print(str(x)*x+'\n')
main(n)
One line, and don't use str:
print((10**(i)//9)*i)
