How to Extract text from given string?

Question

I want to extract a perticular image path string from a given string .

The String is http:\localhost:9090\SpringMVC\images\integration-icon.png

Now i want to get only the path after images like

\images\integration-icon.png

i tried this

Pattern pattern = Pattern.compile("SpringMVC");
Matcher matcher = pattern.matcher(str);
System.out.println("Checking");
if (matcher.find()) {
    System.out.println(matcher.group(1));
}

how can i get ?

If you are using java 7 be aware of Path class docs.oracle.com/javase/7/docs/api/java/nio/file/Path.html — DominikM
– DominikM, Commented Oct 18, 2013 at 11:09

sschrass · Accepted Answer · 2013-10-18 11:14:12Z

2

String filename = filepath.substring(filepath.lastIndexOf("\\") + 1);

or (haven't tried and looks somewhat odd)

String filename = filepath.substring(filepath.lastIndexOf("\\", "images\\".length()) + 1);

edited Oct 18, 2013 at 11:14

answered Oct 18, 2013 at 11:07

sschrass

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Comments

RamonBoza · Accepted Answer · 2013-10-18 11:08:02Z

0

String string = "http:\localhost:9090\ZenoBusinessStore\images\integration-icon.png";
int index = string.indexOf("images\\");
String output = string.substring(index);

answered Oct 18, 2013 at 11:08

RamonBoza

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3 Comments

Ankit Rustagi Over a year ago

wont work, you'll get the error - Invalid escape sequence (valid ones are \b \t \n \f \r \" \' \\ ). Use escape sequences.

RamonBoza Over a year ago

Are you sure? because I used a valid one

Ankit Rustagi Over a year ago

try and run it on a compiler.

AJJ · Accepted Answer · 2013-10-18 11:09:23Z

0

String text = "http:\localhost:9090\SpringMVC\images\integration-icon.png"
String subText = text.subString(text.indexOf("\images"), text.length());
System.out.println(subText);

answered Oct 18, 2013 at 11:09

AJJ

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Comments

Ankit Rustagi · Accepted Answer · 2013-10-18 11:10:20Z

0

String in = "http:\\localhost:9090\\ZenoBusinessStore\\images\\integration-icon.png";
String op = in.replace("http:\\localhost:9090\\ZenoBusinessStore", "");
System.out.println(op);

answered Oct 18, 2013 at 11:10

Ankit Rustagi

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Comments

sschrass · Accepted Answer · 2013-10-18 11:16:01Z

0

ZenoBusinessStore must be the name of your project which is constant. Now split the string

String s = "http:\localhost:9090\ZenoBusinessStore\images\integration-icon.png";
String ary = s.split("ZenoBusinessStore");

Now the 2nd element of the array is your image path.

 System.out.println(ary[1]);

edited Oct 18, 2013 at 11:16

sschrass

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answered Oct 18, 2013 at 11:10

Debabrata

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1 Comment

Ankit Rustagi Over a year ago

wont work, you'll get the error - Invalid escape sequence (valid ones are \b \t \n \f \r \" \' \\ ). Use escape sequences.

Bipin Sahoo · Accepted Answer · 2013-10-18 11:49:59Z

0

Use '\\'. It's because backslash is used in escape sequence like '\n'. With a single \ the compiler have no way to know.

answered Oct 18, 2013 at 11:49

Bipin Sahoo

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