'int' object is not callable exception

Question

Can't find what's wrong with this code. Can someone help me to fix this, please ?

def f(x):
    a = (-5 * (int(x) ** 5) + 69 (int(x) ** 2) - 47)
    return a

print f(0)

Thanks in advance !

Joel Coehoorn · Accepted Answer · 2013-10-18 13:22:17Z

10

An operator is needed between 69 and (int(x) ** 2).
If you meant to use multiplication, then you need to use * explicitly

edited Oct 18, 2013 at 13:22

Joel Coehoorn

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answered Oct 18, 2013 at 13:12

gefei

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1 Comment

smassey Over a year ago

Adding to this correct answer, I'd suggest you break long expressions into smaller chunks and use temporary variables.. It makes the code a bit longer but much more readable, also easier to avoid these kinds of silly syntax errors.

Bucket · Accepted Answer · 2013-10-18 13:19:18Z

4

in this sequence

a = (-5 * (int(x) ** 5) + 69 (int(x) ** 2) - 47)

69 is considered as function call because of the open parenthesis (, so python tries to call 69 as callable but int instance is not callable.

edited Oct 18, 2013 at 13:19

Bucket

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answered Oct 18, 2013 at 13:15

oleg

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Comments

Andy · Accepted Answer · 2013-10-18 13:14:13Z

1

You are missing an operation between the 69 and (int(x) ** 2) in your equation.

answered Oct 18, 2013 at 13:14

Andy♦

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