How can I get data from $.ajax Example:
var ajax = $.ajax({
url: 'http://example.com',
type: 'GET',
dataType: 'json'
});
ajax.url // undefined
// But I need
ajax.url // http://example.com
-
api.jquery.com/jQuery.ajaxSergio– Sergio2013-10-20 19:27:22 +00:00Commented Oct 20, 2013 at 19:27
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2 Answers
You can't. jqXHR objects, such as ajax, don't have properties for (much of?) the request options in the settings object passed to $.ajax().
But, you can keep settings separately and retrieve request info from it as needed:
var settings = {
url: 'http://example.com',
type: 'GET',
dataType: 'json'
};
var ajax = $.ajax(settings);
console.log(settings.url);
And, if needed, you can attach settings to ajax yourself:
// ...
var ajax = $.ajax(settings);
ajax.settings = settings;
console.log(ajax.settings.url);
answered Oct 20, 2013 at 19:30
Jonathan Lonowski
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1 Comment
Benjamin Gruenbaum
So in a sentence, the answer is "No, without modifying the code creating the XHR you can't" ? I see you've edited your answer, you can make the top part more decisive. The answer indeed is "no". james.padolsey.com/jquery/#v=1.10.2&fn=jQuery.ajax see the jqXHR bit :) +1 and cheers.
It was needed for test so I did this way
var ajax = $.ajax({
url: '/signin',
data: { user: 'ButuzGOL' },
type: 'POST',
dataType: 'json'
});
ajax.abort();
ajax.always(function() {
expect(this.type).to.be('POST');
expect(this.url).to.be('/signin');
expect(this.data).to.be({ user: 'ButuzGOL' });
done();
});