discard dynamic characters in string with replace()

Question

for example 21/10/2013.. I want to remove the /2013..

replace('/2013', '') work but the date might be other value like 2014, 2015 and so on

If it's always in this format, could you split, pop, then join? — Dave Chen
– Dave Chen, Commented Oct 21, 2013 at 4:33
@CoreyRothwell: comments are not for answering the question if you know it works - if it does answer the question (which it does), please post it as an answer. Thansk! — Qantas 94 Heavy
– Qantas 94 Heavy, Commented Oct 21, 2013 at 4:53
Why not just .substring(0, 5), assuming the day and month values are zero-padded. — Ja͢ck
– Ja͢ck, Commented Oct 21, 2013 at 5:56
Or .slice(-5), assuming this is not meant to be used in the year 10k+. — Ja͢ck
– Ja͢ck, Commented Oct 21, 2013 at 6:23

omma2289 · Accepted Answer · 2013-10-21 05:51:21Z

2

This removes everything from the last / onwards:

var str = "21/10/2013";
var new_str = str.substring(0,str.lastIndexOf('/'));

answered Oct 21, 2013 at 4:32

omma2289

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Comments

RobG · Accepted Answer · 2013-10-21 04:41:26Z

2

Try:

'21/10/2013'.replace(/\/\d+$/,''); // 21/10

which removes the last "/" and any digits following to the end of the string.

answered Oct 21, 2013 at 4:41

RobG

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