I am trying to use regex to split the string into 2 arrays to turn out like this.
String str1 = "First Second [insideFirst] Third Forth [insideSecond] Fifth";
How do I split str1 to break off into 2 arrays that look like this:
ary1 = ['First Second','Third Forth','Fifth'];
ary2 = ['insideFirst','insideSecond'];
here is my solution
string str = "First Second [insideFirst] Third Forth [insideSecond] Fifth";
MatchCollection matches = Regex.Matches(str,@"\[.*?\]");
string[] arr = matches.Cast<Match>()
.Select(m => m.Groups[0].Value.Trim(new char[]{'[',']'}))
.ToArray();
foreach (string s in arr)
{
Console.WriteLine(s);
}
string[] arr1 = Regex.Split(str,@"\[.*?\]")
.Select(x => x.Trim())
.ToArray();
foreach (string s in arr1)
{
Console.WriteLine(s);
}
Output
insideFirst
insideSecond
First Second
Third Forth
Fifth
[MiddleName], and he certainly was not splitting by [insideFirst]. Even if he MEANT to say square-bracketted-text, he didn't, and I don't think he did. For all we know, he took your answer's c# code, and altered the Regex Patterns in it. He doesn't say. So my point is: The question should be answered as-asked.Plz Try below code. Its working fine for me.
String str1 = "First Second [insideFirst] Third Forth [insideSecond] Fifth";
var output = String.Join(";", Regex.Matches(str1, @"\[(.+?)\]")
.Cast<Match>()
.Select(m => m.Groups[1].Value));
string[] strInsideBreacket = output.Split(';');
for (int i = 0; i < strInsideBreacket.Count(); i++)
{
str1 = str1.Replace("[", ";");
str1 = str1.Replace("]", "");
str1 = str1.Replace(strInsideBreacket[i], "");
}
string[] strRemaining = str1.Split(';');
Plz look at below screen shot of output while debugging code:
Here, strInsideBreacket is array of breacket value like insideFirst andinsideSecond and strRemaining is array of First Second,Third Forth and Fifth
Thanks
SplitByPattern, which returns a collection of the split results, plus a collection of the resulting regex delimiters, your function would only work if the pattern were EXACTLY the Square-Bracket. However, it is obvious by the Test-Data the OP uses that he isn't going to LITERALLY be splitting by square brackets. So your function would fail.Try this solution,
String str1 = "First Second [insideFirst] Third Forth [insideSecond] Fifth";
var allWords = str1.Split(new char[] { '[', ']' }, StringSplitOptions.RemoveEmptyEntries);
var result = allWords.GroupBy(x => x.Contains("inside")).ToArray();
The idea is that, first get all words and then the group it.
\d+\w{2,3}, then this doesn't work. You're coming from a good place, but it doesn't help answer this particular question.It seems to me that "user2828970" asked a question with an example, not with literal text he wanted to parse. In my mind, he could very well have asked this question:
I am trying to use regex to split a string like so.
var exampleSentence = "I had 185 birds but 20 of them flew away"; var regexSplit = Regex.Split(exampleSentence, @"\d+");The result of
regexSplitis:I had,birds but,of them flew away.However, I also want to know the value which resulted in the second string splitting away from its preceding text, and the value which resulted in the third string splitting away from its preceding text. i.e.: I want to know about
185and20.The string could be anything, and the pattern to split by could be anything. The answer should not have hard-coded values.
Well, this simple function will perform that task. The code can be optimized to compile the regex, or re-organized to return multiple collections or different objects. But this is (nearly) the way I use it in production code.
public static List<Tuple<string, string>> RegexSplitDetail(this string text, string pattern)
{
var splitAreas = new List<Tuple<string, string>>();
var regexResult = Regex.Matches(text, pattern);
var regexSplit = Regex.Split(text, pattern);
for (var i = 0; i < regexSplit.Length; i++)
splitAreas.Add(new Tuple<string, string>(i == 0 ? null : regexResult[i - 1].Value, regexSplit[i]));
return splitAreas;
}
...
var result = exampleSentence.RegexSplitDetail(@"\d+");
This would return a single collection which looks like this:
{ null, "I had "}, // First value, had no value splitting it from a predecessor
{"185", " birds but "}, // Second value, split from the preceding string by "185"
{ "20", " of them flew away"} // Third value, split from the preceding string by "20"
Being that this is a .NET Question and, apart from my more favoured approach in my other answer, you can also capture the Split Value another VERY Simple way. You just then need to create a function to utilize the results as you see fit.
var exampleSentence = "I had 185 birds but 20 of them flew away";
var regexSplit = Regex.Split(exampleSentence, @"(\d+)");
The result of regexSplit is: I had, 185, birds but, 20, of them flew away. As you can see, the split values exist within the split results.
Note the subtle difference compared to my other answer. In this regex split, I used a Capture Group around the entire pattern (\d+) You can't do that!!!?.. can you?
Using a Capture Group in a Split will force all capture groups of the Split Value between the Split Result Capture Groups. This can get messy, so I don't suggest doing it. It also forces somebody using your function(s) to know that they have to wrap their regexes in a capture group.
