call another controller using form widget in yii

Question

I'm still grasping Yii framework at the moment and I'm trying to submit a form to go to a specific controller in Yii. What I did was I used a CMSActive Form widget(correct me if I'm wrong)

and the code that I placed:

<?php $form=$this->beginWidget('CMSActiveForm', array(
        'id'=>'file-form',
        'action' => '../controllers/FolderController/actionCreate',
        'enableAjaxValidation'=>false,
)); ?>

I'm trying to call the actionCreate function which is from another controller, so I'm trying to call it but the error 404 that says:

Unable to resolve the request "files/controllers/FolderController/actionCreate".

C:\xampp1.8\htdocs\yii_1.1.13\framework\web\CWebApplication.php

line # 286

0 C:\xampp1.8\htdocs\yii_1.1.13\framework\web\CWebApplication.php(141): CWebApplication->runController('files/controllers/FolderController') 1 C:\xampp1.8\htdocs\yii_1.1.13\framework\base\CApplication.php(169): CWebApplication->processRequest() 2 C:\xampp1.8\htdocs\cubecms\backend\www\index.php(12): CApplication->run() 3 {main}

I'm thinking that it could not see the function since it's an error 404, but am I calling it correctly?

My controller has an actionCreate function, and I'm good once I can get inside the function.

topher · Accepted Answer · 2013-10-23 08:18:58Z

0

action expects a route or a valid url and not a path to the action.

`action`=>array('/controller/action',...)

edited Oct 23, 2013 at 8:18

answered Oct 23, 2013 at 8:12

topher

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2 Comments

marchemike Over a year ago

how do I know the baseurl of the action so I would know where to start?

topher Over a year ago

You should read through yiiframework.com/doc/guide/1.1/en/basics.controller to understand how controllers and actions relate to urls.

VarunBatraIT · Accepted Answer · 2013-10-23 08:23:50Z

0

Place

$this->createUrl('/controller/action');

All url must be made using createUrl or createAbsoluteUrl method.

Here it is in fact url and need not to be /controller/action

If you want it to be submitted on /foo only then place '/foo' in createUrl

answered Oct 23, 2013 at 8:23

VarunBatraIT

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