How to run haskell code that's passed via command argument to the interpreter?

Question

Among other methods, there are a few most common ways to run a haskell program:

ghci, load the file, run main by hand from shell
runhaskell file.hs
ghc file.hs && ./file

I weren't able to find, however, how to run simple code from standard input / command arguments.

For example, standard Lua interpreter will allow you to do:

$ lua -e "print (2+2)"
4

What would be an equivalent of the above for a common Haskell Platform environment?

Would the downvoter please state the reason?

Bartek Banachewicz
– Bartek Banachewicz

2013-10-23 14:27:40 +00:00
Commented Oct 23, 2013 at 14:27 — Bartek Banachewicz
– Bartek Banachewicz, Commented Oct 23, 2013 at 14:27

kqr · Accepted Answer · 2013-10-23 14:23:16Z

6

It's just the same.

$ ghc -e "print (2+2)"
4

answered Oct 23, 2013 at 14:23

kqr

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2 Comments

Bartek Banachewicz Over a year ago

Now I feel a bit dumb, but that answer is a surprising food for thought about more Lua and Haskell similiarities.

Carl Over a year ago

@BartekBanachewicz It's not really Lua and Haskell similarities. More or less every compiler/interpreter has an interface like that on unixy systems. It's just a convention.

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