Memset issue with floating point array in C [duplicate]

Question

I'm trying this simple example to populate a floating point array with 5.6, but upon printing the values out, every value is just 0.0.

#include <string.h>
float testArr[20];
memset(testArr, (float)5.6, 3*sizeof(float));
printf("Value 1: %lf\n",testArr[0]);
printf("Value 2: %lf\n",testArr[1]);
printf("Value 3: %lf\n",testArr[2]);
printf("Value 4: %lf\n",testArr[3]);

I've also tried not casting 5.6 as a float, setting testArr[20] = {} and testArr[20] = {0}, but they also result in the same 0.0.

Read the declaration of memset() and then search for floating-point to integer conversion. None of them are magic. — user529758
– user529758, Commented Oct 26, 2013 at 5:50
memset converts the second parameter to a char. See memset - C++ Reference. — godel9
– godel9, Commented Oct 26, 2013 at 5:50

Drakosha · Accepted Answer · 2013-10-26 05:49:47Z

4

memset fills the memory with 1 char, not float.

answered Oct 26, 2013 at 5:49

Drakosha

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