How to return the pointer in a pointer in a pointer

Question

I feel like this should be very easy, but I am unable to find an applicable question.

X is a shared_ptr<shared_ptr<Item> >.

I have a function that accepts a shared_ptr<Item>

How do I get that inner pointer? I can't just do X ->, and X->get() will return an Item*

Mike Seymour · Accepted Answer · 2013-10-28 18:34:21Z

3

As with a normal pointer, you access a shared pointer's target by dereferencing it:

f(*X);

answered Oct 28, 2013 at 18:34

Mike Seymour

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