Convert a perl regex to a python regex

Question

I'm trying to convert a perl regex to python equivalent.

Line in perl:

($Cur) = $Line =~ m/\s*\<stat\>(.+)\<\/stat\>\s*$/i;

What I've attempted, but doesn't seem to work:

m = re.search('<stat>(.*?)</stat>/i', line)
cur = m.group(0)

Apart from anything else, you need to swap the arguments around: re.search('<stat>(.*?)</stat>/i', line). — rlms
– rlms, Commented Oct 29, 2013 at 21:52
+ means the same thing in Perl and Python, I'm not sure why you'd change (.+) to (.*?). — Nolen Royalty
– Nolen Royalty, Commented Oct 29, 2013 at 21:55
@kylex Are there still problems not addressed by the answers? — rlms
– rlms, Commented Oct 31, 2013 at 16:39

Joran Beasley · Accepted Answer · 2013-10-29 21:51:51Z

5

almost /i means case insensitive

m = re.search(r'<stat>(.*?)</stat>',line,re.IGNORECASE)

also use the r modifier on the string so you dont need to escape stuff like angle brackets.

but my guess is a better solution is to use an html/xml parser like beautifulsoup or other similar packages

answered Oct 29, 2013 at 21:51

Joran Beasley

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hwnd · Accepted Answer · 2015-07-01 18:50:50Z

3

Something like the following ...

r is Python’s raw string notation for regex patterns and to avoid escaping, after the prefix comes your regular expression following your string data. re.I is used for case-insensitive matching.

See the re documentation explaining this in more detail.

To find your match, you could use the group() method of MatchObject like the following:

cur = re.search(r'<stat>([^<]*)</stat>', line).group(1)

Using search() matches only the first occurrence, use findall() to match all occurrences.

matches = re.findall(r'<stat>([^<]*)</stat>', line)

edited Jul 1, 2015 at 18:50

answered Oct 29, 2013 at 23:46

hwnd

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