Converting IPv4 Address to a Hex IPv6 Address in Python

Question

Q: Write a program that prompts the user for an IP address then converts this to a base 10, binary and hex value. The program then converts the hex value to an RFC3056 IPv6 6to4 address.

I have the base 10 and binary parts working but I can't seem to get my head around the hex part. Can the format string method be used somehow to accomplish the same thing? Or would I need to import the ipaddress module in this case?

#!/usr/bin/python3

ip_address = input("Please enter a dot decimal IP Address: ")

"""This part converts to base 10"""
ListA = ip_address.split(".")
ListA = list(map(int, ListA))
ListA = ListA[0]*(256**3) + ListA[1]*(256**2) + ListA[2]*(256**1) + ListA[3]
print("The IP Address in base 10 is: " , ListA)

"""This part converts to base 2"""
base2 = [format(int(x), '08b') for x in ip_address.split('.')]
print("The IP Address in base 2 is: ", base2)

"""This part converts to hex"""
hexIP = []
[hexIP.append(hex(int(x))[2:].zfill(2)) for x in ip_address.split('.')]
hexIP = "".join(hexIP)
print("The IP Address in hex is: " , hexIP)

EDIT: Managed to convert the IP Address to hex value. Now how do I convert this hex value into IPv6 address?

falsetru · Accepted Answer · 2013-11-03 09:36:52Z

7

>>> ip_address = '123.45.67.89'
>>> numbers = list(map(int, ip_address.split('.')))
>>> '2002:{:02x}{:02x}:{:02x}{:02x}::'.format(*numbers)
'2002:7b2d:4359::'

edited Nov 3, 2013 at 9:36

answered Nov 3, 2013 at 8:25

falsetru

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5 Comments

jfs Over a year ago

6to4 address must start with '2002::/16' i.e., '2002:7b2d:4359::' in your example.

user1819786 Over a year ago

Changed it to: '2002:0:0:0:0:ffff:{:02x}{:02x}:{:02x}{:02x}'.format(*numbers)

user1819786 Over a year ago

Doesn't account for the subnet, but it will do for now.

jfs Over a year ago

@user1819786: 0:0:0:0:ffff: is also incorrect in this case. Click both links in my previous comment.

falsetru Over a year ago

@J.F.Sebastian, Thank you for comment and links. I update the answer according to your comment.

jfs · Accepted Answer · 2013-11-08 06:49:49Z

In Python 3.3 you could use ipaddress module to manipulate IPv4, IPv6 addresses:

#!/usr/bin/env python3
import ipaddress

# get ip address 
while True:
    ip4str = input("Enter IPv4 (e.g., 9.254.253.252):")
    try:
        ip4 = ipaddress.IPv4Address(ip4str)
    except ValueError:
        print("invalid ip address. Try, again")
    else:
        break # got ip address

# convert ip4 to rfc 3056 IPv6 6to4 address
# http://tools.ietf.org/html/rfc3056#section-2
prefix6to4 = int(ipaddress.IPv6Address("2002::"))
ip6 = ipaddress.IPv6Address(prefix6to4 | (int(ip4) << 80))
print(ip6)
assert ip6.sixtofour == ip4

# convert ip4 to a base 10
print(int(ip4))
# convert ip4 to binary (0b)
print(bin(int(ip4)))
# convert ip4 to hex (0x)
print(hex(int(ip4)))

Community · Accepted Answer · 2021-10-07 11:07:30Z

2

If you just want to use the IPv4 addresses in an IPv6 context (e.g. by passing to socket.connect() created using the socket.AF_INET6 address family), you can just use the syntax described in RFC4291, Section 2.2:

>>> import socket
>>> a = '10.20.30.40'
>>> s = socket.socket(socket.AF_INET6, socket.SOCK_DGRAM)
>>> s.connect(('2002::' + a, 9))

I.e. just prepend ::ffff: to the IPv4 address and you get a valid 6to4 address. If you instead want to convert this address to the more common hexadecimal form, I suggest using the standard library ipaddress module you mentioned:

>>> import ipaddress
>>> a = '10.20.30.40'
>>> print(ipaddress.IPv6Address('2002::' + a).compressed)
'2002::a14:1e28'

edited Oct 7, 2021 at 11:07

CommunityBot

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answered Aug 23, 2015 at 21:07

Feuermurmel

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Comments

Community · Accepted Answer · 2021-10-07 11:32:16Z

0

Before referring to the solution, have a look at this doc for conversion and convention of ipv6 representation.

def ipconversion4to6(ipv4_address):
    hex_number = ["{:02x}".format(int(_)) for _ in address.split(".")]
    ipv4 = "".join(hex_number)
    ipv6 = "2002:"+ipv4[:4]+":"+ipv4[4:]+"::"
    return ipv6

edited Oct 7, 2021 at 11:32

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answered Dec 22, 2020 at 11:42

shibashis

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