How to loop this program?

Question

def min_payment():
    ''' Calculates the minimum payment due on credit card
        depending on the credit card balance'''
    print("Tiny National Bank of Walterville")
    print("Credit Card Payments")


    balance = float(input("Please enter Credit Card Balance"))
    print("Credit Card Balance: " ,round(float(balance), 2))
    min1 = 12.00
    min2 = round(.027 * balance, 2)

    if min2 > min1:
        print("Minimum payment due: ", min2)

    elif balance <= 0:
        print("No payment due")

    elif balance < min1:
        print("Minimum payment due: ", balance)

    else:
        print("Minimum payment due: ", min1)

If anyone can tell me how to loop that so I can repeat it based on user input, that would be very helpful. I basically want it to say something like this "Another customer (y or n)? "

Asking for the user to select y or n. Also please dont be too critical of the actual code. Im still learning. Its python by the way. Thanks!

If that's python, then where are indentations, by the way?

zubergu
– zubergu

2013-11-04 07:27:11 +00:00
Commented Nov 4, 2013 at 7:27 — zubergu
– zubergu, Commented Nov 4, 2013 at 7:27
You loop it by adding a loop?

Some programmer dude
– Some programmer dude

2013-11-04 07:28:55 +00:00
Commented Nov 4, 2013 at 7:28 — Some programmer dude
– Some programmer dude, Commented Nov 4, 2013 at 7:28

Paul Draper · Accepted Answer · 2013-11-04 07:30:23Z

1

print("Tiny National Bank of Walterville")
print("Credit Card Payments")

while True:
    balance = float(input("Please enter Credit Card Balance"))
    print("Credit Card Balance: " ,round(float(balance), 2))
    min1 = 12.00
    min2 = round(.027 * balance, 2)

    if min2 > min1:
        print("Minimum payment due: ", min2)

    elif balance <= 0:
        print("No payment due")

    elif balance < min1:
        print("Minimum payment due: ", balance)

    else:
        print("Minimum payment due: ", min1)

    answer = ''
    while answer not in ('y', 'n'):
        answer = input("Another customer (y or n)").lower()
    if answer == 'n':
        break

answered Nov 4, 2013 at 7:30

Paul Draper

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Comments

Saad Abdullah · Accepted Answer · 2013-11-04 07:33:53Z

1

isDue=True

while isDue==True:

 balance = float(input("Please enter Credit Card Balance"))
 print("Credit Card Balance: " ,round(float(balance), 2))
 min1 = 12.00
 min2 = round(.027 * balance, 2)

 if min2 > min1:
    print("Minimum payment due: ", min2)

 elif balance <= 0:
     print("No payment due")

 elif balance < min1:
     print("Minimum payment due: ", balance)

 else:
     print("Minimum payment due: ", min1)

//set isDue = False somewhere in while loop

answered Nov 4, 2013 at 7:33

Saad Abdullah

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Comments

WhatsRighteous · Accepted Answer · 2013-11-04 07:29:29Z

0

You can put while True; at the beginning, then take input from customer and if the customer says no make it switch to false.

answered Nov 4, 2013 at 7:29

WhatsRighteous

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Comments

Mandar Parkhi · Accepted Answer · 2019-10-09 11:55:53Z

Outstanding = 59400
interestrate = 4.2

#print("Month", "\t", "Interest+GST", "\t\t", "MinAmtDue", "\t\t\t", "Balance")
#print("-----", "\t\t", "-------", "\t\t", "--------", "\t\t\t", "-------")

month = 0
totpmt = 0
interest_GST = 0
minamtdue = 0
outstandingamt1 = Outstanding
while (outstandingamt1 + interest_GST - minamtdue) > 0 :
    month += 1
    interest_GST = outstandingamt1*4.2/100`enter code here`
    minamtdue = outstandingamt1 * 5/100
    #minamtdue = 12000enter code here
    outstandingamt1 = outstandingamt1 + interest_GST - minamtdue`enter code here`
    print(month, "\t\t\t", round(interest_GST,2), "\t\t", round(minamtdue,2), "\t\t\t", round(outstandingamt1,2))
    totpmt = totpmt + minamtdue
print(month+1, "\t\t\t", 0, "\t\t", round(outstandingamt1,2), "\t\t\t", 0)
print("Total Amount to be paid in ", month+1, "months= ", round(totpmt+outstandingamt1 , 2))

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