ignore second delimiter while spliting string into array

Question

I have a string as follows-

 roger::)

I need to split into two string as roger and :) . I am using the following

"roger::)".split(":")

But this forms three array elements,namely roger,[empty] and ) although what i need is two array elements as roger and :).

enter link description here

I tried using the following link but the console prints undefined for "roger::)".split(/_(.+)?/)[1]

Please Help.

Possible duplicate of stackoverflow.com/questions/2878703/… — user1983983
– user1983983, Commented Nov 8, 2013 at 14:20

plalx · Accepted Answer · 2013-11-08 14:28:42Z

1

Use lookaheads. It will split on a : if followed by :.

"roger::)".split(/:(?=:)/);

However perhaps this is what you want instead. Split on : unless it's a followed by ) which would be an happy face.

"roger::):another:test".split(/:(?!\))/);

edited Nov 8, 2013 at 14:28

answered Nov 8, 2013 at 14:19

plalx

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5 Comments

Mayur Buragohain Over a year ago

"roger::)".split(/:(?=:)/); gives a single array element.However I wanted two array elements.

plalx Over a year ago

@MayurBuragohain I just pasted your code in the console and I get two elements? Which browser are you using?

Mayur Buragohain Over a year ago

i am using it for smiley itself.. testing across firefox,chrome.. "roger::):another:test".split(/:(?!\))/); refuses to accept anything except :)

plalx Over a year ago

@MayurBuragohain That's wierd. Works for me in FF and on gskinner.com/RegExr

plalx Over a year ago

@MayurBuragohain Could you post the result of JSON.stringify("roger::):another:test".split(/:(?!\))/)); ?

RobG · Accepted Answer · 2013-11-08 14:43:19Z

0

Your test case looks limited, perhaps you can just use match:

'roger::)'.match(/[^:]+|:\)/g); // ['roger', ':)']

Maybe that suits, or not:

'roger::):another:test'.match(/[^:]+|:\)/g); // ["roger", ":)", "another", "test"]

answered Nov 8, 2013 at 14:43

RobG

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2 Comments

plalx Over a year ago

Could you confirm the second part of my answer is not working? It works for me, but in an old FF version and I cannot test in another browser right now.

RobG Over a year ago

Both statements in your answer return what I consider correct results in Safari 6.05 and Firefox 24, but testing in older browsers would be much more beneficial. I only suggested alternatives as they don't use look ahead so will suit older browsers.

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