Splitting String array without using split(String regex) method

Question

I have a String array that contains the "_" characheter in each element of it, I want to get rid of these characters.

I can do this task simply by using String [] split(String regex) method, but I don't want to it by this function because I will use this code in J2ME later.

I have write a code to do this task but the output are strange characters [Ljava.lang.String;@19821f [Ljava.lang.String;@addbf1 !!!

public class StringFragementation {

static public   String [] mymethod(String [] mystring)
{

   String ss [] =new String[mystring.length];

   for(int j=0;j<mystring.length;j++)

   {
   ss[j] =  mystring[j].replace('_',',');

   }

   return ss ;

   }
 public static void main(String [] args)

  {

   String []  s = {"Netherlands_Iceland_Norway_Denmark","Usa_Brazil_Argentina"};

   for(int i=0;i<s.length;i++)
   {

 System.out.println("" + mymethod(s) );

   }

       }

       }

Shamse Alam · Accepted Answer · 2013-11-10 10:18:28Z

3

I have modified your code. It will give you desired output. use following code

public static void main(String[] args) {
    String[] s = {"Netherlands_Iceland_Norway_Denmark", "Usa_Brazil_Argentina"};
    String[] finalString = mymethod(s);        
    for (int i = 0; i < s.length; i++) {
        System.out.println("" + finalString[i]);
    }
}

static public String[] mymethod(String[] mystring) {
    String ss[] = new String[mystring.length];
    for (int j = 0; j < mystring.length; j++) {
        ss[j] = mystring[j].replace('_', ',');
    }
    return ss;
}

answered Nov 10, 2013 at 10:18

Shamse Alam

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Comments

Maroun · Accepted Answer · 2013-11-10 09:58:29Z

3

In Java, each object has toString() method, the default is displaying the class name representation, then adding @ and then the hashcode.

ss is an array of Strings. You should use Arrays#toString(), which is implemented this way:

3860     public static String toString(int[] a) { {
3861        if (a == null)
3862            return "null";
3863        int iMax = a.length - 1;
3864        if (iMax == -1)
3865            return "[]";
3866
3867        StringBuilder b = new StringBuilder();
3868        b.append('[');
3869        for (int i = 0; ; i++) {
3870            b.append(a[i]);
3871            if (i == iMax)
3872                return b.append(']').toString();
3873            b.append(", ");
3874        }
3875    }

Or, you can do:

for(String str : mymethod(s)) {
    System.out.println(str);
}

answered Nov 10, 2013 at 9:58

Maroun

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2 Comments

PHPFan Over a year ago

I cann't use Arrays object in j2me version any alternative solution plz?

Maroun Over a year ago

@ElhadiMamoun See "Or, you can do:".

JB Nizet · Accepted Answer · 2013-11-10 09:55:16Z

0

What you see there is the result of the toString() method when invoked on arrays. It's almost meaningless. What is printed is the type of the array followed by its hashCode.

Use java.util.Arrays.toString() to transform an array into a meaningful String representation.

answered Nov 10, 2013 at 9:55

JB Nizet

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2 Comments

PHPFan Over a year ago

I cann't use Arrays object in j2me version any alternative solution plz?

JB Nizet Over a year ago

Yes. So use a for loop. for (String s : array) {System.out.println(s);}

ArtKorchagin · Accepted Answer · 2016-01-10 00:23:29Z

0

public class MyDisticntElements {

    public static void main(String[] args)
    {
        int [] nums = {2,3,4,5,8,7,7};
        MyDisticntElements.printDuplicate(nums);
    }
    public static void printDuplicate(int[] arr)
    {
        for(int i =0; i<arr.length; i++)
        {
            boolean duplicate = false;
            for(int j = 0; j<i; j++)
            {
                if(arr[i] == arr[j])
                {
                    duplicate = true;
                    break;
                }
            }
            if(duplicate)
            {
                System.out.println(arr[i]+"");
            }
        }
    }
}

edited Jan 10, 2016 at 0:23

ArtKorchagin

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answered Jan 9, 2016 at 20:37

Jitendra Chahal

1

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