php detect function is called

Question

I dont know how to explain this question so maybe the tile is not matched.

    Class a {
       function b{
         return $this;
       }
       function c{
         return $this;
       }
    }

If I have class structure like this I can do

$a = new a();
$a->b()->c();

I want to know how can I know the function is not continued like $a->b();, then I return $retuslt instead of $this.

Class a {
   function b{

     //if not continued
     return $result;

     //if continued
     return $this;

   }
   function c{
     return $this;
   }
}

Is this possible? thank you very much!!

I don't think you can do that within PHP. Why would you need to? — Waleed Khan
– Waleed Khan, Commented Nov 11, 2013 at 2:15

cmdprompt · Accepted Answer · 2013-11-11 02:21:52Z

2

It is not possible. You will not know inside the method what is being done with the return. You could however pass a return value in, for example:

Class a {
   function b(&$return){
     // do something 
     $return = 'some value';
     return $this;
   }
   function c(){
     return $this;
   }
}



$a = new a();
$a->b($returnFromB)->c();
echo $returnFromB; // 'some value'

answered Nov 11, 2013 at 2:21

cmdprompt

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1 Comment

Micah Over a year ago

Thank you, I just want to know if its possible.

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